Happy New Year!
After my unannounced blogging sabbatical, I’m happy to be back writing about running and triathlon and all things fitness. Things got pretty hectic on the work front as I began work on a new project, and after all that’s happened to me 2016 still had to add one more insult to injury when I contracted an awful cough and cold that kept me away from training for nearly two weeks.
It is crunch time on my Road to the Ho Chi Minh Run half-marathon and I am nowhere near where I should be at this point. But hey, I know for a fact it’s doable (I’m just gonna have to watch the post-race recovery better). I’m super excited to be starting the year with a trip to a new city and seeing it on foot.
You know, every start of the year I feel hopeful and upbeat. I just came back from my first speed run session in six months. I can’t tell you how happy I was to make it through those 10 rounds of 400 meters and not fall into a paroxysm of coughs. I’m starting to feel like my old self again…
That is, if my old self was sitting at 130 pounds! If this Zenith smart scale I’m currently reviewing is telling me the truth, I am rocking a 15-pound surplus from my racing weight.I had to try on a couple of old evening gowns last night for a wedding I’m attending this week and, well, I’m really filling them out. (They all still zipped up, though. Whew!)
So here’s to starting anew and making a proper go of it, whatever you put your hands to. Whether you exercise to lose weight and build muscle, or train to race faster or longer, don’t just go through the motions. Know you are doing these things for a purpose, and that’s what will make all the effort worthwhile.
This year, I resolve to:
- Sleep earlier — no more staying up ’til 3am playing stupid iPad games!
- Recover better — no scheduling back-to-back races!
- Race more — I miss toeing the start line of our local fun runs!
These resolutions are small things, but I make them that way on purpose so that they’re consistently achievable. What about you? Tell me about your New Year resolutions in the comments. π
